Find 4 consecutive even integers such that when three times the smallest of the intagers is added to twice the largest their sum is 293

If x is the first of the integers then the statement is:

(x), (x+2), (x+4), (x+6)

This means that the smallest is x and the largest is x + 6

so:

3 (x) + 2 (x+6) = 293

3x + 2x + 12 = 293

5x = 281

x = 56.2

This gives us a none integer (decimal)

What now?

Wait remember how x started as the lowest? what if x was the highest instead?

x, x-2, x-4, x-6

so:

3 (x-6) + 2 (x) = 293

5x = 315

x = 62.2

This is as close as have gotten to the answer

Cant seem to get an integer.

Maybe error in the question or some bad math on my part.