The product of some negative number and 3 less than twice that number is 209. find the number

The negative number would most likely be - 19/2

let the negative number be x,

3 less than twice that negative number would be (2x-3)

hence,

equation form

x multiply by (2x-3) equals to 209

it would result in equation

2x^2-3x=209

2x^2-3x-209=0

hence using quadratic eqn

x=11 (rej since qn stated x is a negative number)

x=-19/2