Yolanda watches a carnival game in which a paper cup is tossed. It costs $1 to play the game. If the cup lands upright, the player receives $5. It lands on its side 32 times, up-side down 13 times, and upright 5 times. If Yolanda plays the game ten times, about how many times can she expect to win? How many times can she expect to lose.

Question

Jaydin Cuevas

Mathematics

Today, 03:52

Yolanda watches a carnival game in which a paper cup is tossed. It costs $1 to play the game. If the cup lands upright, the player receives $5. It lands on its side 32 times, up-side down 13 times, and upright 5 times. If Yolanda plays the game ten times, about how many times can she expect to win? How many times can she expect to lose.

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Madisyn Hester · Answer 1

Yolanda only wins if the cup lands upright.

From the experimental data we see that the probability of winning is 5 out of 50, or 10%. Therefore, if Yolanda plays 10 times she can expect to win 10% of 10 times = 1 time. She will lose 9 times.