The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min. A. How long will it be unit the balloons are at the same elevation? B. What will their elevation be then?

Question

Brody Lam

Mathematics

15 December, 07:53

The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min. A. How long will it be unit the balloons are at the same elevation? B. What will their elevation be then?

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Answers (1)

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Russell · Answer 1

Set up the equations as equal:

110x+250=-150x+2200

Add 150x to both sides:

260x+250=2200

Subtract 250 from both sides.

260x=1950

Divide both sides by 260.

x=7.5

A: They will meet at 7.5 minutes after launch

Plug in 7.5:

110 (7.5) + 250=11*75+250=825+250=1075

B: They will meet at 1075 feet