Tom walked at a consistent pace from the economy parking garage to the airport terminal. He stood on a a moving sidewalk for 2/5 of the route, moving at twice his normal walking pace. He made the trip in 6 minutes. On his return trip, the moving sidewalk was out of order, so how long did it take him to walk back?

Question

Kirsten Olsen

Mathematics

22 August, 18:08

Tom walked at a consistent pace from the economy parking garage to the airport terminal. He stood on a a moving sidewalk for 2/5 of the route, moving at twice his normal walking pace. He made the trip in 6 minutes. On his return trip, the moving sidewalk was out of order, so how long did it take him to walk back?

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Gabriela Michael · Answer 1

Let x be the number of minutes for his normal walk

On the way to the airport, for the 2/5 (or 40%) of his route, his speed is twice faster. Hence, the number of x should be divided to 2. The rest of the route (60%) was on his normal pace. The total minutes is 6. The equation is:

0.4 (x:2) + 0.6x = 6

Solving for x, the number of minutes for his normal walk is 7.5 minutes.