A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.

Question

Kason Snow

Mathematics

2 September, 16:55

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.

+5

Answers (2)

Know the Answer?

Hensley · Answer 1

a) L+L+w+w=302

48+w+48+w+w+w=302

96+2w=302

2w=206

w=103

final answer: width is 103feet

length = L=48+w=48+103=151feet

Gia Fields · Answer 2

The first equation would be w+49=l. The second equation would be 2w+2l=302. Now, substitute l in the second equation with the first equation and solve.

2w+2 (w+49) = 302

2w+2w+98=302

4w=204

w=51

l=51+49

l=100

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feeta) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.b) Use the method of substitution to solve the system.

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.