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2 September, 16:55

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.

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Answers (2)
  1. 2 September, 17:09
    0
    a) L+L+w+w=302

    48+w+48+w+w+w=302

    96+2w=302

    2w=206

    w=103

    final answer: width is 103feet

    length = L=48+w=48+103=151feet
  2. 2 September, 17:25
    0
    The first equation would be w+49=l. The second equation would be 2w+2l=302. Now, substitute l in the second equation with the first equation and solve.

    2w+2 (w+49) = 302

    2w+2w+98=302

    4w=204

    w=51

    l=51+49

    l=100
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Home » Mathematics » A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.
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