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4 June, 05:41

what are the dimensions of a rectangle whose length is 4 more than twice the with and whose perimeter is 3 less than 7 times the width

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  1. 4 June, 06:01
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    w = width

    l = 2w+4

    p = 7w-3

    P = 2 (l+w)

    substitute in p = 7w-3 and l = 2w+4

    7w-3 = 2 (2w+4+w)

    combine like terms

    7w-3 = 2 (3w+4)

    distribute

    7w-3 = 6w + 8

    subtract 6w from each side

    w-3 = 8

    add 3 to each side

    w = 11

    l = 2w + 4

    l = 2 (11) + 4 = 22+4 = 26

    P = 7w-3 = 7*11-3 = 77-3 = 74
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