A rectangle has a perimeter of 214 feet. Its length is 9 feet longer than its width. What are the dimensions of the rectangle?

58 feet by 49 feet

Step-by-step explanation:

Let the length be l and the width be w.

Since the perimeter is 214 feet,

2 (l + w) = 214

l + w = 107 (Divide both sides by 2)

l = 107 - w (Make l the subject of the formula)

We also know that the length is 9 feet longer than the width. We can express this as:

l = w + 9

Therefore, by substituting both equations, we get:

w + 9 = 107 - w

2w = 98

w = 49 feet

With this, we can also find the length:

l = 49 + 9

l = 58 feet

Hence the dimension is 58 feet by 49 feet.

The answer is 70ft by 32ft