Ask Question
7 December, 03:07

Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight ... A) 29 and 31. B) 39 and 41. C) 49 and 51

+3
Answers (2)
  1. 7 December, 03:10
    0
    X = 1st number

    x + 2 = 2nd number

    3/7x + 1/3 (x + 2) = 38

    3/7x + 1/3x + 2/3 = 38

    3/7x + 1/3x = 38 - 2/3

    9/21x + 7/21x = 114/3 - 2/3

    16/21x = 112/3

    x = 112/3 * 21/16

    x = 2352/48

    x = 49 < = = 1st number

    x + 2 = 49 + 2 = 51 < = = 2nd number
  2. 7 December, 03:15
    0
    (3/7) x + (1/3) (x + 2) = 38

    Multiply both sides by 21:

    21 * (3/7) x + 21 * (1/3) (x + 2) = 21*38

    9x + 7 (x + 2) = 798

    9x + 7x + 14 = 798

    16x = 784

    x = 49

    x + 2 = 51 so the are 49 and 51
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers