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5 February, 15:20

The graph below shows the velocity f (t) of a runner during a certain time interval: graph of line segment going through ordered pairs 0, 2 and 6, 8. Graph of another line segment going through ordered pairs 6, 8 and 8, 0. Label on the x axis is time in seconds and label on the y axis is velocity in meters per second Which of the following describes the intercepts on the graph? The initial velocity of the runner was 8 m/s, and the runner stopped after 2 seconds. The initial velocity of the runner was 2 m/s, and the runner stopped after 8 seconds. The initial acceleration of the runner was 8 m/s2, and the runner stopped after 2 seconds. The initial acceleration of the runner was 2 m/s2, and the runner stopped after 8 seconds.

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  1. 5 February, 15:25
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    Hi! Answer is "the initial velocity of the runner was 4 m/s, and the runner stopped after 8 seconds".

    This is a velocity - time graph.

    At t = 0 s, the graph has a velocity as 4 m/s. This means, the runner has an initial velocity as 4 m/s.

    At t = 4 s, the runner has reached his maximum velocity as 8 m/s and acceleration is 1 m/s².

    After t = 4 s, the velocity has decreased with the time means it is a negative acceleration.

    At t = 8 s, the velocity of the runner has reached to zero means runner has stopped after 8 seconds.
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Home » Mathematics » The graph below shows the velocity f (t) of a runner during a certain time interval: graph of line segment going through ordered pairs 0, 2 and 6, 8. Graph of another line segment going through ordered pairs 6, 8 and 8, 0.
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