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21 May, 00:11

According to the Rational Root Theorem, the following are potential roots of f (x) = 60x2 - 57x - 18

-6/5, - 1/4, 3, 6

Which is an actual root of f (x) ?

-6/5

-1/4

3

6

+1
Answers (1)
  1. 21 May, 00:21
    0
    The correct answer for the question that is being presented above is this one: "-4 and 3." According to the Rational Root Theorem, the following are potential f (x) 2x2 + 2x 24. The actual roots of the quadratic equation based on the Rational Root Theorem are - 4 and 3.
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