The area of a rectangle is 63m squared, and the length of the rectangle is 5 m more than twice the width. Find the dimensions of the rectangle

Given:

Area (A) = 63m^2

Length (L) = 2W+5

Width (W) = ?

A=LxW

63 = (2W+5) (W)

63=2W^2 + 5W

0=2W^2+5W-63

0 = (2W-9) (W+7)

2W-9=0 then W=4.5 and W+7=0 then W=-7

Can only use 4.5 since it is positive and distance is positive.

W = 4.5 m

L=2W+5=2 (4.5) + 5=9+5=14m