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Today, 10:10

Solve on the interval [0, 2Pi):

1 + cos (theta) = (sqrt (3) + 2) / 2

A. Pi/6, 5Pi/6

B. Pi/3, 5Pi/3

C. Pi/6, 11Pi/6

D. 7Pi/6, 11Pi/6

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Answers (1)
  1. Today, 10:38
    0
    1 + cos t = (√3 + 2) / 2

    cos t = (√3 + 2) / 2 - 1

    cos t = (√3 + 2 - 2) / 2

    cos t = √3/2

    t 1 = π/6, t 2 = 11π/6

    Answer: C) π/6, 11π/6.
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