Daniel is able to land his backflip 60% of the time. He tells his friend that in his next 5 backflips, he will land more than 3 of them. To estimate the probability of this happening, Daniel uses a computer to randomly select 5 numbers from 1 through 5. He lets 1 through 3 represent landing his backflip and 4 and 5 represent not landing it. He repeats this for a total of 22 trials and records the results in the table below. 43113 43323 21245 53154 11545 44511 45221 14221 11123 55131 24535 35133 21454 41314 55242 52214 53542 15231 31244 54541 31415 52522 What is the best estimate, based on this simulation, of the probability that in his next 5 back flips Daniel will land more than 3 of them?

Question

Keegan Hendricks

Mathematics

21 February, 08:05

Daniel is able to land his backflip 60% of the time. He tells his friend that in his next 5 backflips, he will land more than 3 of them. To estimate the probability of this happening, Daniel uses a computer to randomly select 5 numbers from 1 through 5. He lets 1 through 3 represent landing his backflip and 4 and 5 represent not landing it. He repeats this for a total of 22 trials and records the results in the table below. 43113 43323 21245 53154 11545 44511 45221 14221 11123 55131 24535 35133 21454 41314 55242 52214 53542 15231 31244 54541 31415 52522 What is the best estimate, based on this simulation, of the probability that in his next 5 back flips Daniel will land more than 3 of them?

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Heath Shah · Answer 1

We are given the data with the corresponding remarks

43113 - done

43323 - done

21245 - not done

53154 - not done

11545 - not done

44511 - not done

...

Just look at the numbers to see if there are more than 3 digits which are 1,2, and 3. Next, consider done as 100% and not done as 0%. Finally, add all the percentage and take the average. You will get the estimated probability.