Find the sum of the first 44 terms of the following series, to the nearest integer. 10, 14,18, ...

4224

Step-by-step explanation:

Here, we want to calculate the sum of the first 44 digits

Term a which is first digit is 10

common difference which is difference of terms = 14-10 = 18-14 = 4

Now the nth term of an arithmetic sequence is

a + (n-1) d

44th term means n = 44

10 + (44-1) 4

10 + 43 (4)

10 + 172 = 182

To find the sum, we use the formula

Sn = n/2[a + L]

where a is the first term and L is the 44th term

Sn = 44/2 (10 + 182)

Sn = 22 (192)

Sn = 4,224