Find two consecutive odd integers such that their product is 111more than 3 times their sum.

Let the numbers be x-1, x+1

(x-1) (x+1) = 111+3 (x-1+x+1)

x^2-1=111+6x

x^2-6x-112=0

x^2-14x+8x-112=0

x (x-14) + 8 (x-14) = 0

(x-14) (x+8) = 0

x=14,-8

numbers are 14-1,14+1 or 13,15

when x=-8

numbers are - 8-1,-8+1 or - 9,-7