Ask Question
28 August, 16:29

You have 10 batteries sitting on your desk, three of which are dead. You choose 2 batteries are random for you calculator. What is the expected number of good batteries that you get?

A) 0

B) 1

C) 1.4

D) 2

+2
Answers (1)
  1. 28 August, 16:50
    0
    C) 1.4

    Step-by-step explanation:

    The probability of choosing 2 good ones is 7/10·6/9 = 42/90.

    The probability of choosing 1 good one is 7/10·3/9 + 3/10·7/9 = 42/90.

    The probability of choosing 0 good ones is 3/10·2/9 = 6/90

    The expected value is the sum of the product of number of good ones and their probability:

    ... 2·42/90 + 1·42/90 + 0·6/90 = (2+1) ·42/90 = 42/30 = 1.4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “You have 10 batteries sitting on your desk, three of which are dead. You choose 2 batteries are random for you calculator. What is the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers