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1 October, 07:31

How do you solve 3 (2k-2) = - 2 (4k-11)

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  1. 1 October, 07:38
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    1. Distribute 3 to 2k and - 2, also distribute - 2 to 4k and - 11

    2. the equation should look like 6k-6 = - 8k+22

    3. Add - 8k to the other side

    4. add 6 to the other side

    5. it should look like 14k = 28

    6. divide 14 on both side

    7. K = 2
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