Which factorization is incorrect?

1) 4k^2-49 = (2k+7) (2k-7)

2) a^3-8b^3 = (a-2b) (a^2+2ab+4b^2)

3) m^3+3m^2-4m+12 = (m-2) ^2 (m+3)

4) t^3+5t^2+6t+t^2+5t+6 = (t+1) (t+2) (t+3)

Question

Arabella Parrish

Mathematics

2 April, 07:00

Which factorization is incorrect?

1) 4k^2-49 = (2k+7) (2k-7)

2) a^3-8b^3 = (a-2b) (a^2+2ab+4b^2)

3) m^3+3m^2-4m+12 = (m-2) ^2 (m+3)

4) t^3+5t^2+6t+t^2+5t+6 = (t+1) (t+2) (t+3)

+2

Answers (1)

Know the Answer?

Jaylon Reeves · Answer 1

The answer is 3)

Just sub any number you want into the equation and calculate it.

For example of 3)

When m=1

Left hand size=1+3-4+12=12

Right hand size=-1x4=-4

Left hand size≠Right hand size

It is incorrect.

Which factorization is incorrect?1) 4k^2-49 = (2k+7) (2k-7)2) a^3-8b^3 = (a-2b) (a^2+2ab+4b^2)3) m^3+3m^2-4m+12 = (m-2) ^2 (m+3)4) t^3+5t^2+6t+t^2+5t+6 = (t+1) (t+2) (t+3)

Which factorization is incorrect?

1) 4k^2-49 = (2k+7) (2k-7)

2) a^3-8b^3 = (a-2b) (a^2+2ab+4b^2)

3) m^3+3m^2-4m+12 = (m-2) ^2 (m+3)

4) t^3+5t^2+6t+t^2+5t+6 = (t+1) (t+2) (t+3)