Ask Question
21 April, 06:19

Chris needs to make a 500 L of a 35% acidic solution. He has only two of the acidic solutions available, a 25% solution and a 50% solution. How many litres of each acidic solution should he mix? Create a system to solve?

+1
Answers (1)
  1. 21 April, 06:24
    0
    Yes, very fun, not

    ok

    one way is table or

    solutions amount x and y

    x+y=500

    x=25%

    y=50%

    0.25x+0.5y=0.35 (500)

    we have

    x+y=500

    0.25x+0.5y=0.35 (500)

    0.25x+0.5y=175

    solve

    multiply second equation by 100

    25x+50y=17500

    divide everybody by 25

    x+2y=700

    now we have

    x+y=500

    x+2y=700

    multiply first equation by - 1 and add to second equaiton

    -x-y=-500

    x+2y=700 +

    0x+1y=200

    y=200

    sub

    x+y=500

    x+200=500

    x=300

    300L of the 25% and 200L of the 50%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Chris needs to make a 500 L of a 35% acidic solution. He has only two of the acidic solutions available, a 25% solution and a 50% solution. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers