The recommended density of a rectangular aquarium is 7 fish per cubic foot of water. If the owner of the aquarium follows the recommended density guidlines and has 42 fish, what is the height of the aquaruim with a length of 3 feet and a width of 1 foot?

Answer: 2 feets

Step-by-step explanation:

Recommended density = 7 fish / ft^3

If recommended density guideline is followed:

Number of fishes in aquarium = 42

Length of aquarium = 3ft

Width = 1ft

Height = ?

Volume of aquarium = Length * width * height

Volume = 3 * 1 * h = (3ft^2 * h)

Therefore;

If

1ft^3 = 7 fishes

x ft^3 = 42 fishes

Cross multiply

7 (x) ft^3 = 42 fishes

x ft^3 = (42:7)

x ft^3 = 6

Therefore volume of the aquarium with 42 fishes is 6ft^3

Volume = (3ft^2 * h)

6ft^3 = 3ft^2 * h

h = (6ft^3) / (3ft^2)

h = 2ft