If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the hundredths place.

OM=18, so OQ=QM=18/2=9.

Given QU=8

from figure OQU is a right angled triangle, so OU^2=OQ^2 + QU^2

OU^2 = 9*9 + 8*8 = 81+72=153;

OU=sqrt (153) = 12.37 = 13 (approx);

From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13