What are the dimensions of a rectangle that has an area of 30 square meters and a perimeter of 34 meters

L * W = 30

2L + 2W = 34

L = (30/W)

2 (30/W) + 2W = 34

60/W + 2W = 34

Multiply by w to clear the denominator. Bring to one side since it will a quadratic.

60 + 2W^2 - 34W = 0

2W*2 - 34W + 60 = 0

Factor.

2 (w^2 - 17w + 30) = 0

2 (w-15) (w-2) = 0

w=15, w = 2

2 (15) + 2 (2) = 34 perimeter

15 * 2 = 30 area

Dimensions are 15 x 2