An ulcer patient has been told to avoid acidic foods. If he drinks coffee, with a pH of 5.0, it bothers him, but he can tolerate both tap water, with a pH of 5.8, and milk, with a pH of 6.9. In order to make 10 oz of a milk-coffee drink with a pH of 5.8, how many ounces of each are required?

Question

Lyric Coffey

Mathematics

11 February, 21:10

An ulcer patient has been told to avoid acidic foods. If he drinks coffee, with a pH of 5.0, it bothers him, but he can tolerate both tap water, with a pH of 5.8, and milk, with a pH of 6.9. In order to make 10 oz of a milk-coffee drink with a pH of 5.8, how many ounces of each are required?

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Answers (1)

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Donut · Answer 1

The equation should look like:

[H+] = (1-a) (x) + (a) (y)

Where:

5.8 = - log [H+]

5.0 = - log x

6.9 = - log y

(1-a) = proportion of x

a = proportion of y

so calculating a will give you the result of how many ounces are required