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11 July, 12:23

An experiment involves tossing a die. these are some of the events:

a. observe a 2

b. observe an even number

c. observe a number greater than 2

d. observe both a and b

e. observer a or b or both f: observe both a and c find p (a and b)

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Answers (2)
  1. 11 July, 12:26
    0
    "Tossing a die" is assumed to mean choosing a random face of a cube with faces numbered 1 through 6 such that the probability of choosing any particular face (number) is 1/6.

    Event a is "observe a 2". Event b is "observe an even number". The event "a and b" is "observe 2 and an even number". This matches precisely the description for event a. In other words

    ... a and b = a

    ... p (a and b) = p (a) = p (choosing 2) = 1/6
  2. 11 July, 12:27
    0
    Option - B

    An experiment involves tossing a die. these are some of the events during which we can be able to observe an even number.

    Step-by-step explanation:

    It is more obviously to know that there will be six sides for us to observe and each time we will get an even number to observe during the process. So, it all goes with the mechanisms of the probability that are taken under considerations when we speak about such events to happen.
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