An airplane needs to reach a velocity of 203.0 km/h to take off. On a 2000 m runway, what is the minimum acceleration necessary for the plane to take flight?

1.59 m/s²

Step-by-step explanation:

Acceleration = change in Velocity over time. Mathematically it is represented as Δv/Δt

Given values in the question:

Final velocity 203.0 km/h which is equal to (203/3.6) m/s = 56.39 m/s distance 2000 m Initial velocity is 0 m/s

To use the equation for acceleration time is needed.

velocity = distance/time

(203/3.6) = 2000/time mltiplying both sides by time

(203/3.6) x time = 2000 making time subject of the formula

time = 2000 / (203/3.6)

time = 35.47 seconds

Substituting into the acceleration equation

acceleration = Δv/Δt

= (56.39 - 0) / 35.47

= 56.39/35.47

=1.59 m/s²