Use the limit comparison test to determine whether converges or diverges. (a) choose a series with terms of the form and apply the limit comparison test. write your answer as a fully reduced fraction. for, 1/n^7 (b) evaluate the limit in the previous part. enter as infinity and as - infinity. if the limit does not exist, enter dne. = (c) by the limit comparison test, does the series converge, diverge, or is the test inconclusive?

Question

Slade Jones

Mathematics

19 April, 20:09

Use the limit comparison test to determine whether converges or diverges. (a) choose a series with terms of the form and apply the limit comparison test. write your answer as a fully reduced fraction. for, 1/n^7 (b) evaluate the limit in the previous part. enter as infinity and as - infinity. if the limit does not exist, enter dne. = (c) by the limit comparison test, does the series converge, diverge, or is the test inconclusive?

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Answers (1)

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Danica Blackwell · Answer 1

Well, I'm drawing a blank here, but I know the series converges because it is a p-series and p, in this case is 7, is greater than 1, therefore converging.