Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Balance this reaction.

_Al (NO3) 3 (aq) + __Na2SO4 (aq) - > Al2 (SO4) 3 (s) + ___ NaNO3 (aq)

1,3,1,6

2,3,1,6

2,3,1,3

3,3,2,6

2Al (NO₃) ₃ (aq) + 3Na₂SO₄ (aq) → 1Al₂ (SO₄) ₃ (s) + 6NaNO₃ (aq)

2, 3, 1, 6

Second choice.

Step-by-step explanation:

Count the number of atoms on each side. Keep polyatomic ions together because they exist on both sides. After each coefficient you write in, recount the number of atoms.

Al (NO₃) ₃ (aq) + Na₂SO₄ (aq) → Al₂ (SO₄) ₃ (s) + NaNO₃ (aq)

Al 1 Al 2

NO₃ 3 NO₃ 1

Na 2 Na 1

SO₄ 1 SO₄ 3

Balance the sulfates (SO₄) by multiplying it by 3 on the left. Sodium (Na) will also change.

Al (NO₃) ₃ (aq) + 3Na₂SO₄ (aq) → Al₂ (SO₄) ₃ (s) + NaNO₃ (aq)

Al 1 Al 2

NO₃ 3 NO₃ 1

Na 6 Na 1

SO₄ 3 SO₄ 3

Balance sodium (Na) by multiplying it on the left by 6. Nitrate (NO₃) will also change.

Al (NO₃) ₃ (aq) + 3Na₂SO₄ (aq) → Al₂ (SO₄) ₃ (s) + 6NaNO₃ (aq)

Al 1 Al 2

NO₃ 3 NO₃ 6

Na 6 Na 6

SO₄ 3 SO₄ 3

Balance the number of nitrates (NO₃) on the left. Multiply by 2. Aluminum (Al) also changes.

2Al (NO₃) ₃ (aq) + 3Na₂SO₄ (aq) → Al₂ (SO₄) ₃ (s) + 6NaNO₃ (aq)

Al 2 Al 2

NO₃ 6 NO₃ 6

Na 6 Na 6

SO₄ 3 SO₄ 3

The same number of each atom is on each side, so the equation is balanced.

If there is no coefficient, treat it as 1.

2,3,1,6