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Nadeen
Mathematics
25 October, 18:22
What's the axis of symmetry for y=-3x^2+1
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Matias Hull
25 October, 18:44
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y = - 3x^2 + 1 is a quadratic with a = - 3, b = 0 and c = 1.
The equation of the axis of symmetry is x = - b / (2a). Here, that comes out to:
x = 0 / (2*[-3]), or x = 0 (answer)
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