Ask Question
22 December, 10:36

Kyle's family bought 4 adult tickets and 2 student tickets for $52. Maria's family bought 3 adult tickets and 5 student tickets for $60. How much does each type of ticket cost?

+5
Answers (1)
  1. 22 December, 10:48
    0
    Adult tickets cost $10 each and student tickets cost $6 each.

    Given:

    Kyle's family bought 4 adult tickets and 2 student tickets for $52

    Maria's family bought 3 adult tickets and 5 student tickets for 60.

    Let us assign x as the adult tickets and y as the students tickets

    Kyle's family: 4x + 2y = 52

    Maria's family: 3x + 5y = 60

    Let us find the value of x using Kyle's equation:

    4x + 2y = 52

    4x = 52 - 2y

    x = (52 - 2y) / 4

    x = 13 - y/2

    Substitute the value of x in Maria's equation to find y.

    3x + 5y = 60

    3 (13 - y/2) + 5y = 60

    39 - 3y/2 + 5y = 60

    - 3y/2 + 5y = 60 - 39

    - 3y/2 + 5y = 21

    2 (-3y/2 + 5y) = 2 (21)

    -3y + 10y = 42

    7y = 42

    7y/7 = 42/7

    y = 6

    x = 13 - y/2

    x = 13 - 6/2

    x = 13 - 3

    x = 10

    To check:

    Kyle's Family Maria's Family

    4x + 2y = 52 3x + 5y = 60

    4 (10) + 2 (6) = 52 3 (10) + 5 (6) = 60

    40 + 12 = 52 30 + 30 = 60

    52 = 52 60 = 60
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Kyle's family bought 4 adult tickets and 2 student tickets for $52. Maria's family bought 3 adult tickets and 5 student tickets for $60. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers