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22 August, 14:00

One plane at 520 feet is ascending at a rate of 40 feet per minute, while another plane at 3800 feet is descending at a rate of 120 feet per minute. how long will it take the two lanes to be at the same altitude?

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  1. 22 August, 14:13
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    Plane A 520 feet vertical rise 40 feet/min

    plane B 3800 feet vertical dip 120 feet per minute.

    vertically the speeds are 40 feet / minute & 120 feet / minute.

    120 + 40 = 160 feet per minute.

    the distance between them = 3800 - 520 = 3280 feet

    t = d/r

    3280/160

    t = 20.5 minutes. they will be at the same altitude.
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