Angie has some red and blue beads. 40% of her beads were red. When she lost 50 blue beads, the number of blue beads was reduced by 1/3 its original number of beads. How many beads did Angie have in the end?

Question

Raphael Gallegos

Mathematics

2 September, 11:30

Angie has some red and blue beads. 40% of her beads were red. When she lost 50 blue beads, the number of blue beads was reduced by 1/3 its original number of beads. How many beads did Angie have in the end?

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Answers (1)

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Rowan · Answer 1

Step-by-step explanation:

Let x represent the total number of red and blue beads

Angie has some red and blue beads. 40% of her beads were red. This means that the total number of red beads is

40/100 * x = 0.4x

The number of blue beads would be

x - 0.4x = 0.6x

When she lost 50 blue beads, the number of blue beads was reduced by 1/3 its original number of beads. This means that

0.6x - 50 = 0.6x - 0.6x/3

0.6x - 50 = 0.6x - 0.2x = 0.4x

0.6x - 0.4x = 50

0.2x = 50

x = 50/0.2 = 250

The number of blue beads that Angie had initially is

0.6 * 250 = 150

The number of blue beads that Angie has left is

150 - 50 = 100 beads

The number of beads that Angie has in the end is

250 - 50 = 200 beads