Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?

A) x=2k+4

B) x=2k+12

C) x=2k-1/4

D) x=1/4+12

Question

Tiana Padilla

Mathematics

12 November, 22:51

Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?

A) x=2k+4

B) x=2k+12

C) x=2k-1/4

D) x=1/4+12

+5

Answers (1)

Know the Answer?

Genevieve Clarke · Answer 1

A) 2k+4

Step-by-step explanation:

To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.

To start, we will cross multiply. If we have a/b=c/d, then ad=bc

We can perform the same calculation here,

6/x=3 / (k+2)

6 (k+2) = 3x

Divide both sides by 3

2 (k+2) = x

x=2k+4

Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?A) x=2k+4B) x=2k+12C) x=2k-1/4D) x=1/4+12

Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?

A) x=2k+4

B) x=2k+12

C) x=2k-1/4

D) x=1/4+12