A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how many of each type she has: 17 peanuts, 9 cashews, 12 almonds, and 10 walnuts.

Armando scoops out a bowl of 32 nuts. About how many should he expect to be cashews?

A. 5

B. 6

C. 9

D. 18

Question

Marin Cunningham

Mathematics

11 October, 06:05

A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how many of each type she has: 17 peanuts, 9 cashews, 12 almonds, and 10 walnuts.

Armando scoops out a bowl of 32 nuts. About how many should he expect to be cashews?

A. 5

B. 6

C. 9

D. 18

+4

Answers (1)

Know the Answer?

Pete · Answer 1

17 + 9 + 12 + 10 = 48 total nuts ... out of those 48, 9 were cashews

9/48 = x / 32 ... 9 cashews to 48 nuts = x cashews to 32 nuts

cross multiply

(48) (x) = (9) (32)

48x = 288

x = 288/48

x = 6 ... so there is expected to be 6 cashews out of 32 nuts