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4 April, 12:07

In how many ways can a committee of 4 be chosen from a group of 9 people?

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  1. 4 April, 12:24
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    Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.

    C=n! / (k! (n-k) !) where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices. In this case:

    C=9! / (4! (9-4) !)

    C=9! / (4!5!)

    C=362880 / (24*120)

    C=362880/2880

    C=126

    So there are 126 unique ways to pick 4 people from a group of 9 people.
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