An object moves along the x-axis, its position at each time t> 0 given by / "x (t) = 81/2t^2-3/4t^4/" Determine the time interval (s), if any, during which the object slows down.

Question

Jaylene

Mathematics

1 May, 02:08

An object moves along the x-axis, its position at each time t> 0 given by / "x (t) = 81/2t^2-3/4t^4/" Determine the time interval (s), if any, during which the object slows down.

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Pecan · Answer 1

You can say an object slow down when the acceleration is negative which can be observed on a negative slope during the graph of acceleration, from a position equation lets derive 2 times to attain the acceleration equation

x (t) = 81/2*t^2-3/4*t^4

V (t) = 81X - 3t^3

A (t) = 81 - 9t^2

81 - 9t^2 < 0

t^2 > 9

-3 > t > 3

An object moves along the x-axis, its position at each time t> 0 given by / "x (t) = 81/2*t^2-3/4*t^4/" Determine the time interval (s), if any, during which the object slows down.

An object moves along the x-axis, its position at each time t> 0 given by / "x (t) = 81/2t^2-3/4t^4/" Determine the time interval (s), if any, during which the object slows down.