Let x be normally distributed with mean μ = 133 and standard deviation σ = 23. use table 1.

a. find p (x ≤ 100). (round "z" value to 2 decimal places and final answer to 4 decimal places.) p (x ≤ 100)

b. find p (95 ≤ x ≤ 110). (round "z" value to 2 decimal places and final answer to 4 decimal places.) p (95 ≤ x ≤ 110)

c. find x such that p (x ≤ x) = 0.350. (round "z" value and final answer to 2 decimal places.) x

d. find x such that p (x > x) = 0.920. (round "z" value and final answer to 2 decimal places.)

Question

16 September, 21:28

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Abel Mack · Answer 1

A) z value = (x - π) / σ = 100 - 133 / 23 = - 1.43

p (< = 100) = 0.0764