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25 August, 23:35

How many 5-digit numbers can be formed from the integers 1, 2, ..., 9 if no digit can appear more than twice?

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  1. 25 August, 23:57
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    5 digit number with no repeats

    1st digit has 9 possibilities

    2nd digit has 8 possibilities

    3rd digit has 7 possibilities

    4th digit has 6 possibilities

    5th fight has 5 possibilities

    Therefore the answer is:

    9 x 8 x 7 x 6 x 5 = 72 x 210 = 15,120
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