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19 January, 14:32

Last question!. Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold for a total of $10,680. How many unlimited-ride passes were sold?

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  1. 19 January, 14:42
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    see you know that there were 282

    passes sold right so the equation is x+y=282

    where x and y are the respective types of tickets sold

    now x+y=282

    hence y=282-x

    now see the amount collect is $10680

    that is = >50x+20y=10680 ...

    try to think a lil' here now substitute that equation which i gave you in the previous comment and viola ... you get x to be 168
  2. 19 January, 14:59
    0
    To answer the question, let x be the number of unlimited-ride pass for $50 and y be the number of entrance-only pass for $20. The following equations are useful to answer the question above,

    x + y = 282

    50x + 20y = 10,680

    Solving for the variables above gives x = 168 and y = 114.

    Therefore, there are 168 unlimited-ride passes that were sold.
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