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4 March, 01:49

Find the dimensions of the rectangular box with largest volume if the total surface area is given as 64cm^2

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  1. 4 March, 02:16
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    Let x = lenght, y = width, and z = height

    The volume of the box is equal to V = xyz

    Subject to the surface area

    S = 2xy + 2xz + 2yz = 64

    = 2 (xy + xz + yz)

    = 2[xy + x (64/xy) + y (64/xy) ]

    S (x, y) = 2 (xy + 64/y + 64/x)

    Then

    Mx (x, y) = y = 64/x^2

    My (x, y) = x = 64/y^2

    y^2 = 64/x

    (64/x^2) ^2 = 64

    4096/x^4 = 64/x

    x^3 = 4096/64

    x^3 = 64

    x = 4

    y = 64/x^2

    y = 4

    z = 64/yx

    z = 64/16

    z = 4

    Therefor the dimensions are cube 4.
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