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21 November, 17:37

What is the domain of the function? y=sqrt (4x+8)

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  1. 21 November, 17:53
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    Obviously (hopefully) a square root function cannot be negative.

    Also, 4x-8 must be > = 0, otherwise the sqrt is undefined for the reals.

    4x-8 > = 0

    4x > = 8

    x > = 2

    Then the range is [0, inf)

    The domain is [2, inf)
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