It takes the first pipe 9 more hours to fill the pool than the first and the second pipes together and 7 less hours than it would take the second pipe if it was working alone. How long would it take to fill up the pool if both pipes were working together?

Question

Aniyah Bullock

Mathematics

29 January, 20:07

It takes the first pipe 9 more hours to fill the pool than the first and the second pipes together and 7 less hours than it would take the second pipe if it was working alone. How long would it take to fill up the pool if both pipes were working together?

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Answers (1)

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Ryker · Answer 1

Let the time taken for the first pipe to fill the pool be x hours

time taken for second pipe to fill the pool is (x+7) hours

time taken for both pipes to fill the pull = (x-9) hours

thus fraction of time taken for both will be written as:

1 / (x-9)

thus total fraction for pipe 1 and 2 will be

1/x+1 / (x+7) = 1 / (x-9)

solving for x we get:

x=-3 or x=21

but time is positive, then time taken by first pipe is 21 hours

time taken by both pipes will be 21-9=12 hours