A representative from a company that manufactures items for left-handed people will attend a large convention. The representative hopes to find a left-handed person at the convention to try out the items. The representative will select an attendee at random until a left-handed person is found. Assume each selection is independent of another. If 10 percent of the convention attendees are left-handed, what is the probability that the representative must select 4 attendees to find one who is left-handed

Question

London Mccann

Mathematics

26 April, 23:19

A representative from a company that manufactures items for left-handed people will attend a large convention. The representative hopes to find a left-handed person at the convention to try out the items. The representative will select an attendee at random until a left-handed person is found. Assume each selection is independent of another. If 10 percent of the convention attendees are left-handed, what is the probability that the representative must select 4 attendees to find one who is left-handed

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Britney Velez · Answer 1

Answer:.1 (0.9^3)

Step-by-step explanation:

We are given the following information:

We treat left banded as a success.

P (left handed) = 10% = 0.1

Then the number of attendees follows a geometric distribution, where

P (X=x) = p (1-p) ^x-1

where x is the number of trails to get first success.

Now, we are given x = 4

=.1 (.9) ^3