The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 54 ft2. find the dimensions of the rectangle.

A = L * W

A = 54

L = 2W + 3

54 = W (2W + 3)

54 = 2W^2 + 3W

2W^2 + 3W - 54 = 0

(2W - 9) (W + 6) = 0

2W - 9 = 0

2W = 9

W = 9/2

W = 4.5 < = = width

W + 6 = 0

W = - 6 ... it wont be this one because it is negative

L = 2W + 3

L = 2 (4.5) + 3

L = 9 + 3

L = 12 <==length