The length of a rectangle is 11 inches greater than twice the width. of the diagonal is 2 inches more than the length, find the dimensions of the rectangle

Width = W

length=2w+11

diagonal=2w+13

use the Pythagorean Theorem

(2w+13) ^2=w^2 + (2w+11) ^2

4w^2+52w+169=w^2+4w^2+44w+121

simplify

52w+169=w^2+44w+121

w^2+44w-52w-169+121=0

w^2-8w-48=0

factor

(w-12) (w+4) = 0

w-12=0

w=12 inches (width)

l=2*12+11=35 inches (length)