A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?

a. 2.25 s; 9 ft

b. 1.13 s; 31.5 ft

c. 1.13 s; 69.75 ft

d. 1.13 s; 29.25 ft

Question

Cheyenne Pennington

Mathematics

30 August, 22:38

A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?

a. 2.25 s; 9 ft

b. 1.13 s; 31.5 ft

c. 1.13 s; 69.75 ft

d. 1.13 s; 29.25 ft

+2

Answers (1)

Know the Answer?

Cailyn Bell · Answer 1

H = - 16t^2 + 36t + 9

At maximum height h' = 0,

h' = - 32t + 36 = 0

32t = 36

t = 36/32 = 1.13 s.

Maximum height = - 16 (1.125) ^2 + 36 (1.125) + 9 = 29.25 ft

Answer is option d (1.13 s, 29.25 ft)