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31 January, 17:46

Compare the investment below to an investment of the same principal at the same rate compounded annually principal: $9000 annual interest: 8% interest periods: 6 number of years: 12

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  1. 31 January, 17:48
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    Step-by-step explanation:

    We would apply the formula for determining compound interest which is expressed as

    A = P (1+r/n) ^nt

    Where

    A = total amount in the account at the end of t years

    r represents the interest rate.

    n represents the periodic interval at which it was compounded.

    P represents the principal or initial amount deposited

    Considering the investment compounded annually,

    From the information given,

    P = 9000

    r = 8% = 8/100 = 0.08

    n = 1 because it was compounded once in a year.

    t = 12 years

    Therefore,

    A = 9000 (1 + 0.08/1) ^1 * 12

    A = 9000 (1.08) ^12

    A = $22664

    For the second investment,

    n = 6

    Therefore,

    A = 9000 (1 + 0.08/6) ^6 * 12

    A = 9000 (1 + 0.0133) ^72

    A = 9000 (1.0133) ^72

    A = $23301

    The second investment gave higher returns.
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