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23 June, 04:46

Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general admissions sold as there were kids tickets, and the total receipts were $7750, how many of each type of ticket were sold?

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  1. 23 June, 04:57
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    There was 3000 general admission tickets sold and 500 kid ticket sold.

    How did I get this?

    First, we need to see what information we have.

    $2.50 = General admission tickets = (G)

    $0.50 = kids tickets = (K)

    There were 6x as many general admission tickets sold as kids. G = 6K

    We need two equations:

    G = 6K

    $2.50G + $.50K = $7750

    Since, G = 6K we can substitute that into the 2nd equation.

    2.50 (6K) +.50K = 7750

    Distribute 2.50 into the parenthesis

    15K +.50K = 7750

    combine like terms

    15.50K = 7750

    Divide both sides by 15.50, the left side will cancel out.

    K = 7750/15.50

    K = 500 tickets

    So, 500 kid tickets were sold.

    Plug K into our first equation (G = 6k)

    G = 6*500

    G = 3000 tickets

    So, 3000 general admission tickets were sold,

    Let's check this:

    $2.50 (3000 tickets) = $7500 (cost of general admission tickets)

    $.50 (500 tickets) = $250 (cost of general admission tickets)

    $7500 + $250 = $7750 (total cost of tickets)
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