How do you factor the quadratic

J (x) = (x-4) ^2 - 2

Question

Cesar Haas

Mathematics

3 February, 22:04

How do you factor the quadratic

J (x) = (x-4) ^2 - 2

+4

Answers (1)

Know the Answer?

Lucas Hess · Answer 1

Step-by-step explanation:

I assume you mean you want to find the roots. Simply set J (x) equal to 0 and solve for x.

0 = (x - 4) ² - 2

2 = (x - 4) ²

±√2 = x - 4

x = 4 ± √2

The roots are x = 4 - √2 and x = 4 + √2. J (x) can be written in factored form as:

J (x) = (x - (4 - √2)) (x - (4 + √2))

J (x) = (x - 4 + √2) (x - 4 - √2)

How do you factor the quadraticJ (x) = (x-4) ^2 - 2

How do you factor the quadratic

J (x) = (x-4) ^2 - 2