Use the table below to evaluate d/dx [f[g (2x) ]] at x = 1

x 1 2 3 4 f (x) 6 1 8 2 f ' (x) 6 1 8 2 g (x) 1 4 4 3 g ' (x) 9 5 5 - 4 I don't know how to continue with this question. i know [g (2x) ]=8 ... pretty sure

Question

Bruno Henry

Mathematics

27 July, 13:55

Use the table below to evaluate d/dx [f[g (2x) ]] at x = 1

x 1 2 3 4 f (x) 6 1 8 2 f ' (x) 6 1 8 2 g (x) 1 4 4 3 g ' (x) 9 5 5 - 4 I don't know how to continue with this question. i know [g (2x) ]=8 ... pretty sure

+4

Answers (1)

Know the Answer?

Libby King · Answer 1

X f (x) f' (x) g (x) g' (x)

1 6 6 1 9

2 1 1 4 5

3 8 8 4 5

4 2 2 3 - 4

What is asked is d/dx [f[g (2x) ]] at x = 1

g (2x) at x = 1 is

g (2) = 4

f (g (2x) = f (g (2)) = f (4)

d/dx f (4) = f'' (4) = 2

The answer is 2

Use the table below to evaluate d/dx [f[g (2x) ]] at x = 1x 1 2 3 4 f (x) 6 1 8 2 f ' (x) 6 1 8 2 g (x) 1 4 4 3 g ' (x) 9 5 5 - 4 I don't know how to continue with this question. i know [g (2x) ]=8 ... pretty sure

Use the table below to evaluate d/dx [f[g (2x) ]] at x = 1

x 1 2 3 4 f (x) 6 1 8 2 f ' (x) 6 1 8 2 g (x) 1 4 4 3 g ' (x) 9 5 5 - 4 I don't know how to continue with this question. i know [g (2x) ]=8 ... pretty sure